2.5L R3 pannier problem

[MrPix]

As you cannot repeat the numbers it is a permutation (not a combination) for the sake of calculating the number of possible outcomes.

The total number is 10! / (10 - 3)!, in English Ten Factorial divided by the Factorial of ten (number of available digits) minus three (number of times the digit is used).

or 10! / 7! = 3,628,800 / 5,040 = 720

Still not sure it applies to the combination lock on the panniers... assuming that each number is fully placed.

There are 1000 possibilities... surely ... I can't see any repeated sequences here.. please circle the 280 that are there to help me.

 

[technoguppy]

Found them, they are right there!

 

[barbagris]

This will sort it

Tsk -

 

[Grumpy Ole Codger]

Photos or it didn't happen!

 

[barbagris]

Last time I used one of those was ............... covered by the Official Secrets act.

 

[G Williams]

Still not sure it applies to the combination lock on the panniers... assuming that each number is fully placed.

There are 1000 possibilities... surely ... I can't see any repeated sequences here.. please circle the 280 that are there to help me.

There are 1,000 in total, but only 720 where each number in a group of 3 is unique. e.g. 221, 222, 212 etc are not included in the 720

 

[MrPix]

There are 1,000 in total, but only 720 where each number in a group of 3 is unique. e.g. 221, 222, 212 etc are not included in the 720

I get the advanced math, but this was in context of how may different numbers would need to be tried to open the panniers...

If the OP only tried the 720, there is a 28% chance he would not open the lock as it could be one of the 280 sequences possible that were not attempted. It's all clever semantics on the word 'combination' rather than on the actual reality of opening the pannier's lock... I get that.. but even so...

In reality, the numbers can be shifted off center in tiny increments and these count too... so the number goes up by 'a lot' (not a mathematical term).

It's a moot point as the pedantic dealer obviously only tried the 720 on the permutation lock before declaring defeat and the locks faulty!

 

[Bigjaype]

If you count from 000 to 999, with a shot of whiskey between each count, how many combinations do you think you'll get to?

 

[MrPix]

If you count from 000 to 999, with a shot of whiskey between each count, how many combinations do you think you'll get to?

Upmteen?

 

[MrPix]

Interesting that your example indicates 953 numbers and not 1,000 . . .

Err ok.., rest my case. 47 columns of 21 and a column of 13 ....