TuneECU vs TuneBoy vs Triumph Diagnostic

[R-III-R Turbo]

A mildly interesting fact that the TPS/ISCV voltages read differently in Triumph's own diagnostics software, versus in the TuneECU and TuneBoy we all know and use.

TuneECU and TuneBoy appear to read 0.02v or more higher on the TPS/ISCV than Triumph's own diagnostic software.

Would this be the reason some people find the bike idle & low % throttle control works better with a slightly higher TPS/ISCV setting on TuneECU?

 

[FE_rex]

1 A/D count off a 5V 8 bit system ??????

 

[Tripps]

1 A/D count off a 5V 8 bit system ??????

In English?

 

[FE_rex]

analog signals are usually digitized to be read by a computer or other numerical based processor. The resolution of an analog signal is infinite, however the resolution of a digital signal must be limited or it would require an infinite amount of memory. Sensors typically convert physical signals (pressure, position, level etc) to voltages or currents which are then digitized for use of the numerical processor.

Disclaimer - I'm not sure how Triumph does this OR even if 5 volts is the range of the sensor OR if the processor uses 8 bits. It may just be a remarkable coincident that this works out.

What does 1 A/D count off a 5V 8 bit system mean:
The above hieroglyphics relate a system where the analog (A) range is 0-5V. In the case of an 8-bit system, the 5V range would be converted into 2^8 (256) digital bins (aka counts). Each bin represents a range of (5V)/ (256 bins/counts) = 0.0195V. As the numerical processor reads only the digitized signal, it can only discern a difference of 0.0195V.

For example
0-0.0195V - 0 Count
0.0196 - 0.0391V - 1 Count
0.0391V - 0.0586V 2 Counts

In most cases the resolution of an A to D converter is +/- one count. It is also affected by what you consider to be 0 counts. Numerical averaging and other signal processing is why you don't typically see numbers jump by the resolution of 1 counts.

 

[scot in exile]

analog signals are usually digitized to be read by a computer or other numerical based processor. The resolution of an analog signal is infinite, however the resolution of a digital signal must be limited or it would require an infinite amount of memory. Sensors typically convert physical signals (pressure, position, level etc) to voltages or currents which are then digitized for use of the numerical processor.

Disclaimer - I'm not sure how Triumph does this OR even if 5 volts is the range of the sensor OR if the processor uses 8 bits. It may just be a remarkable coincident that this works out.

What does 1 A/D count off a 5V 8 bit system mean:
The above hieroglyphics relate a system where the analog (A) range is 0-5V. In the case of an 8-bit system, the 5V range would be converted into 2^8 (256) digital bins (aka counts). Each bin represents a range of (5V)/ (256 bins/counts) = 0.0195V. As the numerical processor reads only the digitized signal, it can only discern a difference of 0.0195V.

For example
0-0.0195V - 0 Count
0.0196 - 0.0391V - 1 Count
0.0391V - 0.0586V 2 Counts

In most cases the resolution of an A to D converter is +/- one count. It is also affected by what you consider to be 0 counts. Numerical averaging and other signal processing is why you don't typically see numbers jump by the resolution of 1 counts.

Now that makes more sense why did you not say that in the first place

 

[Tripps]

Thanks, got it. .02, approximate. Why analog recordings are said to sound better to someone with better ears than I. Digital deals in discrete samples.

 

[CrzystghndKC]

analog signals are usually digitized to be read by a computer or other numerical based processor. The resolution of an analog signal is infinite, however the resolution of a digital signal must be limited or it would require an infinite amount of memory. Sensors typically convert physical signals (pressure, position, level etc) to voltages or currents which are then digitized for use of the numerical processor.

Disclaimer - I'm not sure how Triumph does this OR even if 5 volts is the range of the sensor OR if the processor uses 8 bits. It may just be a remarkable coincident that this works out.

What does 1 A/D count off a 5V 8 bit system mean:
The above hieroglyphics relate a system where the analog (A) range is 0-5V. In the case of an 8-bit system, the 5V range would be converted into 2^8 (256) digital bins (aka counts). Each bin represents a range of (5V)/ (256 bins/counts) = 0.0195V. As the numerical processor reads only the digitized signal, it can only discern a difference of 0.0195V.

For example
0-0.0195V - 0 Count
0.0196 - 0.0391V - 1 Count
0.0391V - 0.0586V 2 Counts

In most cases the resolution of an A to D converter is +/- one count. It is also affected by what you consider to be 0 counts. Numerical averaging and other signal processing is why you don't typically see numbers jump by the resolution of 1 counts.

Oh hell yes. Once again blinded by science.